Allow a name to be shown even if parsing recipe failed

If recipe parsing failed the pn field will be blank, but for display
purposes we can take a guess from the filename.

Signed-off-by: Paul Eggleton <paul.eggleton@linux.intel.com>

layerindex/detail.html

@@ -173,7 +173,7 @@
                         <tbody>
                             {% for recipe in layeritem.sorted_recipes %}
                                 <tr>
-                                    <td><a href="{{ recipe.vcs_web_url }}">{{ recipe.pn }}</a></td>
+                                    <td><a href="{{ recipe.vcs_web_url }}">{{ recipe.name }}</a></td>
                                     <td>{{ recipe.pv }}</td>
                                     <td>{{ recipe.short_desc }}</td>
                                 </tr>

layerindex/models.py

@@ -118,5 +118,11 @@ class Recipe(models.Model):
         else:
             return self.description
 
+    def name(self):
+        if self.pn:
+            return self.pn
+        else:
+            return self.filename.split('_')[0]
+
     def __unicode__(self):
         return os.path.join(self.filepath, self.filename)

layerindex/recipes.html

@@ -53,7 +53,7 @@
                     <tbody>
                         {% for recipe in recipe_list %}
                             <tr>
-                                <td><a href="{{ recipe.vcs_web_url }}">{{ recipe.pn }}</a></td>
+                                <td><a href="{{ recipe.vcs_web_url }}">{{ recipe.name }}</a></td>
                                 <td>{{ recipe.pv }}</td>
                                 <td>{{ recipe.short_desc }}</td>
                                 <td><a href="{% url layer_item recipe.layer.name %}">{{ recipe.layer.name }}</a></td>