Show count of layers to be reviewed next to Review link

Add a badge next to the Review link (when shown for users with the
publish permission) on all pages showing how many layers need to be
reviewed, if any.

Signed-off-by: Paul Eggleton <paul.eggleton@linux.intel.com>

TODO

@@ -16,7 +16,6 @@ Later:
 * Style/extend about page?
 * Style recipe info page?
 * Style machine list on detail
-* Show count of layers to be reviewed next to review button
 * Something to help with compatibility (although maybe this should just be handled using the existing versioned layer dependencies in layer.conf)
 * Query backend service? i.e. special URL to query information for external apps/scripts
 * Tool for finding/comparing duplicate recipes?

base.html

@@ -53,7 +53,12 @@
                     {% block submitlink %}<li><a href="{% url submit_layer %}">Submit layer</a></li>{% endblock %}
                     {% if user.is_authenticated %}
                     {% if perms.layeritem.publish_layer %}
-                        <li><a href="{% url layer_list_review %}">Review</a></li>
+                        <li><a href="{% url layer_list_review %}">
+                            Review
+                            {% if unpublished_count > 0 %}
+                            <span class="badge badge-warning">{{ unpublished_count }}</span>
+                            {% endif %}
+                        </a></li>
                     {% endif %}
                     <li class="divider-vertical"></li>
                     <li class="dropdown">

layerindex/context_processors.py

@@ -4,7 +4,7 @@
 #
 # Licensed under the MIT license, see COPYING.MIT for details
 
-from layerindex.models import Branch
+from layerindex.models import Branch, LayerItem
 
 def layerindex_context(request):
     current_branch = request.session.get('branch', None)
@@ -13,4 +13,5 @@ def layerindex_context(request):
     return {
         'all_branches': Branch.objects.all(),
         'current_branch': current_branch,
+        'unpublished_count': LayerItem.objects.filter(status='N').count(),
     }