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perf expr: Use macros for operators
No functional change, switch the operators to use macros so that additional complexity for constants can be added in a later change. Signed-off-by: Ian Rogers <irogers@google.com> Tested-by: John Garry <john.garry@huawei.com> Acked-by: Jiri Olsa <jolsa@redhat.com> Cc: Alexander Shishkin <alexander.shishkin@linux.intel.com> Cc: Andi Kleen <ak@linux.intel.com> Cc: Ingo Molnar <mingo@redhat.com> Cc: Jin Yao <yao.jin@linux.intel.com> Cc: Kajol Jain <kjain@linux.ibm.com> Cc: Mark Rutland <mark.rutland@arm.com> Cc: Namhyung Kim <namhyung@kernel.org> Cc: Paul Clarke <pc@us.ibm.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Sandeep Dasgupta <sdasgup@google.com> Cc: Stephane Eranian <eranian@google.com> Link: https://lore.kernel.org/r/20210923074616.674826-6-irogers@google.com Signed-off-by: Arnaldo Carvalho de Melo <acme@redhat.com>
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@ -43,6 +43,12 @@ static void expr_error(double *final_val __maybe_unused,
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pr_debug("%s\n", s);
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}
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#define BINARY_LONG_OP(RESULT, OP, LHS, RHS) \
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RESULT = (long)LHS OP (long)RHS;
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#define BINARY_OP(RESULT, OP, LHS, RHS) \
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RESULT = LHS OP RHS;
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%}
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%%
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@ -81,14 +87,14 @@ expr: NUMBER
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free($1);
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}
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| expr '|' expr { $$ = (long)$1 | (long)$3; }
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| expr '&' expr { $$ = (long)$1 & (long)$3; }
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| expr '^' expr { $$ = (long)$1 ^ (long)$3; }
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| expr '<' expr { $$ = $1 < $3; }
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| expr '>' expr { $$ = $1 > $3; }
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| expr '+' expr { $$ = $1 + $3; }
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| expr '-' expr { $$ = $1 - $3; }
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| expr '*' expr { $$ = $1 * $3; }
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| expr '|' expr { BINARY_LONG_OP($$, |, $1, $3); }
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| expr '&' expr { BINARY_LONG_OP($$, &, $1, $3); }
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| expr '^' expr { BINARY_LONG_OP($$, ^, $1, $3); }
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| expr '<' expr { BINARY_OP($$, <, $1, $3); }
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| expr '>' expr { BINARY_OP($$, >, $1, $3); }
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| expr '+' expr { BINARY_OP($$, +, $1, $3); }
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| expr '-' expr { BINARY_OP($$, -, $1, $3); }
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| expr '*' expr { BINARY_OP($$, *, $1, $3); }
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| expr '/' expr { if ($3 == 0) {
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pr_debug("division by zero\n");
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YYABORT;
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