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perf ftrace: Fix display for range of the first bucket

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When min_latency is not given, it prints 0 - 0.  It should be 0 - 1.

Before:

  $ sudo ./perf ftrace latency -a -T do_futex sleep 1
  #   DURATION     |      COUNT | GRAPH                                          |
       0 -    0 us |        321 | ###########                                    |
  ...

After:

  $ sudo ./perf ftrace latency -a -T do_futex sleep 1
  #   DURATION     |      COUNT | GRAPH                                          |
       0 -    1 us |        699 | ############                                   |
  ...

Fixes: 08b875b6bf ("perf ftrace latency: Introduce --min-latency to narrow down into a latency range")
Reviewed-by: Gabriele Monaco <gmonaco@redhat.com>
Signed-off-by: Namhyung Kim <namhyung@kernel.org>
Tested-by: Arnaldo Carvalho de Melo <acme@redhat.com>
Tested-by: Gabriele Monaco <gmonaco@redhat.com
Cc: Adrian Hunter <adrian.hunter@intel.com>
Cc: Ian Rogers <irogers@google.com>
Cc: Ingo Molnar <mingo@kernel.org>
Cc: Jiri Olsa <jolsa@kernel.org>
Cc: Kan Liang <kan.liang@linux.intel.com>
Cc: Peter Zijlstra <peterz@infradead.org>
Link: https://lore.kernel.org/r/20250108210015.1188531-2-namhyung@kernel.org
Signed-off-by: Arnaldo Carvalho de Melo <acme@redhat.com>
This commit is contained in:
Namhyung Kim 2025-01-08 13:00:15 -08:00 committed by Arnaldo Carvalho de Melo
parent dd01b985c5
commit 510f0247cd
1 changed files with 1 additions and 1 deletions
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2
tools/perf/builtin-ftrace.c
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@ -840,7 +840,7 @@ static void display_histogram(struct perf_ftrace *ftrace, int buckets[])
bar_len = buckets[0] * bar_total / total; bar_len = buckets[0] * bar_total / total;
printf(" %4d - %4d %s | %10d | %.*s%*s |\n", printf(" %4d - %4d %s | %10d | %.*s%*s |\n",
0, min_latency, use_nsec ? "ns" : "us", 0, min_latency ?: 1, use_nsec ? "ns" : "us",
buckets[0], bar_len, bar, bar_total - bar_len, ""); buckets[0], bar_len, bar, bar_total - bar_len, "");
for (i = 1; i < NUM_BUCKET - 1; i++) { for (i = 1; i < NUM_BUCKET - 1; i++) {