meta-openembedded/meta-python/recipes-devtools/python/python-pycurl.inc
Pierre-Jean Texier cab232ac59 python3-pycurl: upgrade 7.43.0.3 -> 7.43.0.5
License-Update: copyright years updated

-Copyright (C) 2013-2019 by Oleg Pudeyev <oleg at bsdpower.com>
+Copyright (C) 2013-2020 by Oleg Pudeyev <oleg at bsdpower.com>

Signed-off-by: Pierre-Jean Texier <pjtexier@koncepto.io>
Signed-off-by: Khem Raj <raj.khem@gmail.com>
2020-03-04 18:54:32 -08:00

26 lines
762 B
HTML

SUMMARY = "A Python Interface To The cURL library"
DESCRIPTION = "\
PycURL is a Python interface to libcurl, the multiprotocol file \
transfer library. Similarly to the urllib Python module, PycURL can \
be used to fetch objects identified by a URL from a Python program \
"
SECTION = "devel/python"
HOMEPAGE = "http://pycurl.io/"
LICENSE = "LGPLv2 | MIT"
LIC_FILES_CHKSUM = "file://COPYING-LGPL;md5=4fbd65380cdd255951079008b364516c \
file://COPYING-MIT;md5=60872a112595004233b769b6cbfd65b6 \
"
SRC_URI[md5sum] = "0b387d4609ed20c88baede8579a4d425"
SRC_URI[sha256sum] = "ec7dd291545842295b7b56c12c90ffad2976cc7070c98d7b1517b7b6cd5994b3"
inherit pypi
PYPI_PACKAGE = "pycurl"
DEPENDS = "\
curl \
${PYTHON_PN}\
"