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License-Update: copyright years updated -Copyright (C) 2013-2019 by Oleg Pudeyev <oleg at bsdpower.com> +Copyright (C) 2013-2020 by Oleg Pudeyev <oleg at bsdpower.com> Signed-off-by: Pierre-Jean Texier <pjtexier@koncepto.io> Signed-off-by: Khem Raj <raj.khem@gmail.com>
26 lines
762 B
HTML
26 lines
762 B
HTML
SUMMARY = "A Python Interface To The cURL library"
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DESCRIPTION = "\
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PycURL is a Python interface to libcurl, the multiprotocol file \
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transfer library. Similarly to the urllib Python module, PycURL can \
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be used to fetch objects identified by a URL from a Python program \
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"
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SECTION = "devel/python"
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HOMEPAGE = "http://pycurl.io/"
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LICENSE = "LGPLv2 | MIT"
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LIC_FILES_CHKSUM = "file://COPYING-LGPL;md5=4fbd65380cdd255951079008b364516c \
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file://COPYING-MIT;md5=60872a112595004233b769b6cbfd65b6 \
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"
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SRC_URI[md5sum] = "0b387d4609ed20c88baede8579a4d425"
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SRC_URI[sha256sum] = "ec7dd291545842295b7b56c12c90ffad2976cc7070c98d7b1517b7b6cd5994b3"
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inherit pypi
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PYPI_PACKAGE = "pycurl"
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DEPENDS = "\
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curl \
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${PYTHON_PN}\
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"
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