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recipetool: create: extract name of package from a repository
For git repositories in the absence of any other indicator, it's not an unreasonable assumption that the name of the repository is the name of the software package it contains, so use that as PN if we don't have anything else. (From OE-Core rev: ef73fa70f0955912b0da140922465a3c817424e9) Signed-off-by: Paul Eggleton <paul.eggleton@linux.intel.com> Signed-off-by: Ross Burton <ross.burton@intel.com> Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
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@ -339,9 +339,14 @@ def determine_from_url(srcuri):
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pn = res.group(1).strip().replace('_', '-')
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pv = res.group(2).strip().replace('_', '.')
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if not pn and not pv and parseres.scheme not in ['git', 'gitsm', 'svn', 'hg']:
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srcfile = os.path.basename(parseres.path.rstrip('/'))
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pn, pv = determine_from_filename(srcfile)
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if not pn and not pv:
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if parseres.scheme not in ['git', 'gitsm', 'svn', 'hg']:
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srcfile = os.path.basename(parseres.path.rstrip('/'))
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pn, pv = determine_from_filename(srcfile)
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elif parseres.scheme in ['git', 'gitsm']:
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pn = os.path.basename(parseres.path.rstrip('/')).lower().replace('_', '-')
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if pn.endswith('.git'):
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pn = pn[:-4]
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logger.debug('Determined from source URL: name = "%s", version = "%s"' % (pn, pv))
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return (pn, pv)
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