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The default return value from subprocess.check_output is an encoded byte. The applied fix will decode the value to a string. (From OE-Core rev: 046769fa952a511865c416b80d10af6287147fb7) Signed-off-by: Pawel Zalewski <pzalewski@thegoodpenguin.co.uk> Signed-off-by: Alexandre Belloni <alexandre.belloni@bootlin.com> Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
31 lines
1.1 KiB
Plaintext
31 lines
1.1 KiB
Plaintext
#
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# Copyright OpenEmbedded Contributors
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#
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# SPDX-License-Identifier: MIT
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#
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# Extract UUID from ${ROOTFS}, which must have been built
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# by the time that this function gets called. Only works
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# on ext file systems and depends on tune2fs.
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def get_rootfs_uuid(d):
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import subprocess
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rootfs = d.getVar('ROOTFS')
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output = subprocess.check_output(['tune2fs', '-l', rootfs], text=True)
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for line in output.split('\n'):
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if line.startswith('Filesystem UUID:'):
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uuid = line.split()[-1]
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bb.note('UUID of %s: %s' % (rootfs, uuid))
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return uuid
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bb.fatal('Could not determine filesystem UUID of %s' % rootfs)
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# Replace the special <<uuid-of-rootfs>> inside a string (like the
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# root= APPEND string in a syslinux.cfg or systemd-boot entry) with the
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# actual UUID of the rootfs. Does nothing if the special string
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# is not used.
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def replace_rootfs_uuid(d, string):
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UUID_PLACEHOLDER = '<<uuid-of-rootfs>>'
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if UUID_PLACEHOLDER in string:
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uuid = get_rootfs_uuid(d)
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string = string.replace(UUID_PLACEHOLDER, uuid)
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return string
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